y=√ [sinx+ √ {sinx + √ (sinx+ ----- upto ♾️)}] Then (dy/ dx) = cos x /( 2y -1)
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y=1+1/x + 1/x^2 + 1/x^3 + -----------upto infinity , | x| greater than 1 Then (dy /dx)= -( y/x)^2
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y√ ( x^2 + 1) = log { √( x^2 +1) - x} Then ( x^2 + 1 )(dy/ dx) + xy+ 1= 0 || DIFFERENTIATION
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