y=√ [sinx+ √ {sinx + √ (sinx+ ----- upto ♾️)}] Then (dy/ dx) = cos x /( 2y -1)
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y=1+1/x + 1/x^2 + 1/x^3 + -----------upto infinity , | x| greater than 1 Then (dy /dx)= -( y/x)^2
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y= √{t- A) /(B- t)} and x= √{( t- A)(B- t)} Then (dy/dx) = ? |DIFFERENTIATION | Special Substitution
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y= arc tan { cosx /( 1+ sin x) }+ sin ( e^x) Then 2( dy/ dx) + 1= 2e^x cos ( e^x)
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এসএসসি ২০২৫ গণিত CQ সমাধান | Sylhet Board 2022 Math Solution | SSC Math Chapter 3
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