y= arc tan { cosx /( 1+ sin x) }+ sin ( e^x) Then 2( dy/ dx) + 1= 2e^x cos ( e^x)
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y= arc sin {(3cosx + 4sinx) /5} Then ( dy/ dx) = 1 || DERIVATIVE | INVERSE CIRCULAR FUNCTIONS
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Resolvendo um exame de admissão à Universidade de Stanford | x=?
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y= arc cos [ x^2 + √ ( 1- x) ( 1- x^3) ] || DIFFERENTIATION
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CLASS 10 VERY VERY IMPORTANT QUESTIONS FOR YOUR BOARD EXAMINATION.
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4{ arc tan (1/3) + arc cos ( 2/√5)} = π || INVERSE TRIGONOMETRIC FUNCTIONS
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Uma Equação Exponencial DIABÓLICA! 😈🔥
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Worst Fails of the Year | Try Not to Laugh 💩
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