FOURIER SERIES f(x) = |cos x| in interval x (- pi to +pi)
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FOURIER SERIES: f(x)=1+(2x/pi) (x=-pi to 0) 1-(2x/pi) (x=0 to +pi) Deduce Π^2/8 = 1+1/3^2 + ...
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Find the complex form of Fourier series of f(x)=e^-x in x = -1 to +1
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Fourier half range cosine series : f(x)=kx (x=0 to l/2) : k(l-x) (x=l/2 to 1)
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Fourier cosine series of f(x) = x
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Expand f(x)=x cos〖x 〗 as Fourier series in the interval (-π,π)#Mathematics#aktu
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@btechmathshub7050Fourier series f(x)=|sinx|
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Introdução ao Cálculo Diferencial e Integral - 02.04.2016 - parte 1
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