#26 || Problem#4 || Solve : (𝒅^𝟐 π’š)/〖𝒅𝒙〗^𝟐 +πŸ‘ π’…π’š/𝒅𝒙+πŸπ’š=γ€–πŸ’π’„π’π’”γ€—^𝟐 𝒙 || 18MAT21 || BMATC101 || BMATM101

4:57

#27 Problem#5 Solve : (𝒅^𝟐 π’š)/〖𝒅𝒙〗^𝟐 +π’š=πŸ”πŸ“π’„π’π’”(πŸπ’™+𝟏).

12:00

#21 || Problem#3 Solve : (𝒅^𝟐 π’š)/〖𝒅𝒙〗^𝟐 βˆ’πŸ’π’š=𝒄𝒐𝒔𝒉(πŸπ’™βˆ’πŸ)+πŸ‘^𝒙 || 18MAT21 ||

9:03

#30 || Problem#1|| Type : 3 || Solve :π’š^β€²β€²+πŸ‘π’š^β€²+πŸπ’š=γ€–πŸπŸπ’™γ€—^𝟐 ||

14:10

#41 || Problem#1|| Cauchy’s linear equation || 𝒙^𝟐 (𝒅^𝟐 π’š)/〖𝒅𝒙〗^𝟐 βˆ’πŸ‘π’™ π’…π’š/𝒅𝒙+πŸ’π’š=(𝟏+𝒙^𝟐) || 18MAT21||

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HOW to solve //limxβ†’0 ( tanx x ) 1⁄xL'Hospital Rule-(tanx/x)^1/x

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Clairaut's Differential Equation|Clairauts| Engineering Mathematics|VTU|GIT|RCU|PUC| #maths

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