級數求和 sum of sin(n)/n (傅立葉級數）
13:03
Finding a closed form for ζ(4)
20:19
Parseval's Theorem (Fourier series engineering mathematics)
25:35
加個1怎麼難那麼多? 級數1/(1+n^2)的和是什麼? Sum of 1/(1+n^2)
16:40
L'incroyable addition 1+2+3+4+...=-1/12 - Micmaths
11:59
Sum of 1/n^4 (Fourier Series & Parseval's Theorem)
13:22
Fourier Series of e^x from -pi to pi (fourier series engineering mathematics)
13:40
Le calcul qui divise : 6÷2(1+2) - Micmaths
11:28