FOURIER SERIES Change of interval f(x) = 2x-x^2 in (0 3)
16:40
FOURIER SERIES f(x) = pix x=0 to 1 pi(2-x) x=1 to 2 Deduce Π^2/8 = 1 + 1/3^2 + 1/5^2 +...
17:53
FOURIER SERIES f(x) = |cos x| in interval x (- pi to +pi)
13:10
Fourier series of f(x) = (pi-x)/2 x= 0 to 2pi Deduce Π/4 = 1 - 1/3 + 1/5 - 1/7 + ...
12:25
Fourier series of f(x)=-k x=-pi to 0 k x=0 to pi Deduce Π/4=1-1/3+1/5-...
13:53
Fourier Series of 2x-x^2 over (0, 3) || 18mat31 || Dr Prashant Patil
8:35
FOURIER SERIES f(x) =-pi if x=-pi to 0 x if x=0 to pi
13:19
FOURIER SERIES f(x)=x^2 in x=-pi to pi Find Π^2/6 Π^2/8 Π^2/12
11:26